Election results in the London Borough of Sutton.
Du kannst nicht mehr als 25 Themen auswählen Themen müssen entweder mit einem Buchstaben oder einer Ziffer beginnen. Sie können Bindestriche („-“) enthalten und bis zu 35 Zeichen lang sein.

vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
vor 14 Jahren
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172
  1. - @page_title = @ward.name + " Ward Candidates"
  2. - if @postcode
  3. .grid_12
  4. %h2.noprint
  5. These are the candidates for
  6. = @postcode
  7. .clear
  8. .grid_6
  9. %h1.adr
  10. %span.locality
  11. = @ward.constituency.name
  12. MP candidates
  13. .grid_6
  14. %h1.adr
  15. %span.locality
  16. = @ward.name
  17. ward
  18. council candidates
  19. .clear
  20. .grid_6
  21. %p
  22. You can vote for
  23. %strong ONE
  24. of these people to become your member of parliament.
  25. %p.noprint
  26. Find out more about
  27. %a{ :href => '/how-the-parliament-election-works' } how the parliament election works.
  28. .grid_6
  29. %p
  30. You can vote for
  31. %strong THREE
  32. of these people to become your local councillors.
  33. %p.noprint
  34. Find out more about
  35. %a{ :href => '/how-the-council-election-works' } how the council election works.
  36. .clear
  37. .grid_6
  38. - for candidate in @ward.constituency.parliamentcandidates
  39. %p.vcard
  40. %span.candidate_name.fn
  41. = candidate.forenames.split(' ')[0]
  42. = candidate.surname
  43. %br
  44. %span.candidate_party.org
  45. = candidate.party.name
  46. %p.highlight
  47. This list of candidates may be incomplete as people have until
  48. %strong 20 April
  49. to decide whether they want to stand for election as the
  50. = @ward.constituency.name
  51. MP.
  52. .grid_6
  53. - for candidate in @ward.councilcandidates
  54. %p.vcard
  55. %span.candidate_name.fn
  56. = candidate.forenames.split(' ')[0]
  57. = candidate.surname
  58. %br
  59. %span.candidate_party.org
  60. = candidate.party.name